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10p^2+30p=0
a = 10; b = 30; c = 0;
Δ = b2-4ac
Δ = 302-4·10·0
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-30}{2*10}=\frac{-60}{20} =-3 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+30}{2*10}=\frac{0}{20} =0 $
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